Question

a =32m/s^2 , v =20 m/s , u=10km/h , s=?, t=? find the distance and time taken. Please find the answer fast​

Answer 1

Answer:

The answers are t = 0.5 secs and s = 6.12 m.

Step-by-step explanation:

As we know that for a uniformly accelerated motion of any particular particle we have the following equations of motion.

v = u + a×t

s = u×t + $\frac{1}{2} at^{2}$

$v^{2} - u^{2} = 2as$

Where the used signs have their usual meanings as given below:

v = the final velocity

u = the initial velocity

s = the displacement

a = the acceleration

t = the time

we have the following,

a = 32 $m/s^{2}$ , u = 10 km/hr = 2.78 m /s , v = 20 m /s

We are keen to use the third equation here as follows:

$v^{2} -u^{2} =2as$

⇒ $20^{2} -2.78^{2} = 2(32)$ × s

⇒ 400 - 7.7284 = 64 × s

⇒ 64 × s = 392.2716

⇒ s = 392.2716 ÷ 64

⇒ s = 6.12 m

Now we have to find the time by the first equation as below:

v = u + a × t

⇒ 20 = 2.78 + 32 × t

⇒ 32 t = 20 - 2.78

⇒ 32 t = 17.22

⇒ t = 17.22 ÷ 32

⇒ t = 0.5 secs

Therefore the t = 0.5 secs and s = 6.12 m.