A 330 ohm resistor is in series with the parallel combination of four 1kilo ohm resistors. a 100v source is connected to the circuit. which resistor has the most current throught it
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We know that the current through series resistors will be same and parallel resistor with minimum resistance will have minimum current.
By finding Requivalent = 580 ohm we get current in the circuit = 100/580
So current through 330ohm resistor = 200/580
Again as all 1kiloohm resistor are in parallel so current through each will be 1/4th. so current through one 1000ohm resistor = (100/580)÷4 = 25/580.
25/580 < 200/580. So current through the 330ohm resistor will be maximum = 300/580
By finding Requivalent = 580 ohm we get current in the circuit = 100/580
So current through 330ohm resistor = 200/580
Again as all 1kiloohm resistor are in parallel so current through each will be 1/4th. so current through one 1000ohm resistor = (100/580)÷4 = 25/580.
25/580 < 200/580. So current through the 330ohm resistor will be maximum = 300/580
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