a) 34.3 kW
A elevator is designed to lift a load of 1000 kg through 6 floors of a building, averaging 3.5 m per
floor in 6 seconds. The power of the engine of the elevator, neglecting other losses is given by
b) 27.5 kW
c) 20.5 kW
d) 15.2 kW [ ]
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Answer:
b) 27.5 kW will be the answer please mark me as brainliest
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Given the elevator is going up a height of 6×3.5m in 6 seconds
increase in potential energy of the system PE will be
△PE=mgh
now, power is defined as energy used or spent per unit time
P=△PE/△t
P=
P = 3.43 x 10 W
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