Math, asked by ananikajenet123, 4 months ago

a) 340 b) 32 C) R30
then the population n
yearsye
a) 40% b) 45% c) 5%
11) The compound interest on 15000 at 12% p.a. for 2 years,compounded
annually is
a) 1272 b) <1500 c) *1300
12) The compound interest on 8000 at 10% p.a. for 1 year compounded half
yearly is ...
a) 500 b) 3820 c) *700
13) The annual rate of growth in population of a town is 10% if it's present
population is 26620
then the population 3 years ago was
a) 25000 b) 15000 c) 20000
14) If the compound interest is calculated quarterly, the amount is found using
the formula...
a) A=P[1+c/400)*ñ b) A = P[1+r/100)" () A=P[1*1/100]"
15) The difference between the Cland S.1 for 2 years for a principal of 25000
at the rate of interest 8% p.a. is.
16) Depreciation value is calculated by the formula .P(1-1/100]n
a) True b) False
17) If the present population of a P and it increases at the rate of rpla
P(1+r/10015
a) True b) False
18) The present value of a machine is 16800.It depreciated at 25% pajts
worth
after 2 years is 19450
a) True b) False
19)The time taken for <1000 to become (1331 at 20% pa, compounded
annually​

Answers

Answered by snehithshailesh
0

Answer:

i don't know sorry sorry pls forgive me

I don't know sorry

Step-by-step explanation:

sorry sorry

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