a 35 m long ladder just reaches a window of a building. If ladder makes an angle theta with the level ground such that tantheta = 1/2root 6. Find the height of the window
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let theta=x, height of window=h,
given that tanx=1/2root6
sinx=P/H=h/35;
now, tanx=1/cotx
therefore cotx=2root6;
Now, 1+cot^2x=cosec^2x
put the values
1+24=cosec^2x;
cosecx=5
Now, cosecx=1/sinx=5
So, 35/h=5
Therefore, h=7
So, the height of the window above the ground level is 7 metres.
given that tanx=1/2root6
sinx=P/H=h/35;
now, tanx=1/cotx
therefore cotx=2root6;
Now, 1+cot^2x=cosec^2x
put the values
1+24=cosec^2x;
cosecx=5
Now, cosecx=1/sinx=5
So, 35/h=5
Therefore, h=7
So, the height of the window above the ground level is 7 metres.
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