Question

A 3500 kg car starting from rest attains a speed of 25.0 m/s in 30.0 s. What is the force of the car?

Answer 1

Answer :-

• Force (F) = $\boxed{\textsf{\textbf{\red{ 2916.67\:N}}}}$

Given :-

• Mass of the car (m) = 3500 kg

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 25 m/s

• Time taken (t) = 30 s

To find :-

• Force of the car.

Formula used :-

• $\boxed{\sf{a = \left(\dfrac{v-u}{t}\right)}}$

• $\boxed{\sf{F = ma}}$

Solution :-

➪ $\sf{a = \left(\dfrac{v-u}{t}\right)}$

➪ $\sf{a = \left(\dfrac{25-0}{30}\right)}$

➪ $\sf{a = \dfrac{5}{6}\:m/s²}$

$\:$

➪ $\sf{F = ma}$

➪ $\sf{F = 3500\times \dfrac{5}{6}}$

➪ $\sf{\red{F = 2916.67\:N}}$