Question

A 36-gram sample of water has an initial temperature of 22°C. After the sample absorbs 1200 joules of heat energy, what is the final temperature of the sample?

Answer 1

Answer:

The final temperature of the water is 29.96 °C.

Explanation:

Mass of water = m = 36 g

Specific heat of water = c = 4.186 J/g°C

Heat absorbed by the water = Q = 1200 Joules

Change in temperature = $\Delta T$

$Q=mc\Delta T=1200 J=36 g\times 4.186 J/g^oC\times \Delta T$

$\Delta T=7.96^oC=T_f-T_i=T_f-22^oC$

$T_f=29.96^oC$

The final temperature of the water is 29.96 °C.