a 36 m tree broke due to storm at apoint but did not get seperate its top touched the ground a distance of 10m from its base find the height of the points from the ground at which the tree was brokem
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total height of the tree = 36m
let the height of the standing part be x
then the broken part = 36- x
the entire thing will form a right angled triangle
whose
base (ground) = 10m
hypotenuse = 36 - x
perpendicular = x
by pythagoras theorem
(36 - x )^2 = x^2 + 10^2
1296 - 72x + x^2 = x^2 + 100
1296 - 100 = 72x
72x = 1196
x = 16.61
the answer is 16.61 m
let the height of the standing part be x
then the broken part = 36- x
the entire thing will form a right angled triangle
whose
base (ground) = 10m
hypotenuse = 36 - x
perpendicular = x
by pythagoras theorem
(36 - x )^2 = x^2 + 10^2
1296 - 72x + x^2 = x^2 + 100
1296 - 100 = 72x
72x = 1196
x = 16.61
the answer is 16.61 m
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