Math, asked by rosebabu630gmailcom, 1 day ago

a - (3a - (2a - 5)/10) - (2a - 57)/6 = - 5/3​

Answers

Answered by varadad25
8

Question:

Find the value of a.

\displaystyle{\sf\:a\:-\:\left(\:3a\:-\:\dfrac{2a\:-\:5}{10}\:\right)\:-\:\left(\:\dfrac{2a\:-\:57}{6}\:\right)\:=\:-\:\dfrac{5}{3}}

Answer:

The value of a is 5.

Step-by-step-explanation:

The given equation is

\displaystyle{\sf\:a\:-\:\left(\:3a\:-\:\dfrac{2a\:-\:5}{10}\:\right)\:-\:\left(\:\dfrac{2a\:-\:57}{6}\:\right)\:=\:-\:\dfrac{5}{3}}

We have to find the value of a.

Now,

\displaystyle{\sf\:a\:-\:\left(\:3a\:-\:\dfrac{2a\:-\:5}{10}\:\right)\:-\:\left(\:\dfrac{2a\:-\:57}{6}\:\right)\:=\:-\:\dfrac{5}{3}}

\displaystyle{\implies\sf\:a\:-\:\left(\:\dfrac{30a\:-\:(\:2a\:-\:5\:)}{10}\:\right)\:=\:\dfrac{-\:5}{3}\:+\:\left(\:\dfrac{2a\:-\:57}{6}\:\right)}

\displaystyle{\implies\sf\:a\:-\:\left(\:\dfrac{30a\:-\:2a\:+\:5}{10}\:\right)\:=\:\dfrac{-\:5\:\times\:2}{3\:\times\:2}\:+\:\left(\:\dfrac{2a\:-\:57}{6}\:\right)}

\displaystyle{\implies\sf\:a\:-\:\left(\:\dfrac{28a\:+\:5}{10}\:\right)\:=\:\dfrac{-\:10}{6}\:+\:\left(\:\dfrac{2a\:-\:57}{6}\:\right)}

\displaystyle{\implies\sf\:a\:-\:\left(\:\dfrac{28a\:+\:5}{10}\:\right)\:=\:\dfrac{-\:10}{6}\:+\:\dfrac{2a\:-\:57}{6}}

\displaystyle{\implies\sf\:a\:-\:\left(\:\dfrac{28a\:+\:5}{10}\:\right)\:=\:\dfrac{-\:10\:+\:2a\:-\:57}{6}}

\displaystyle{\implies\sf\:a\:=\:\dfrac{2a\:-\:10\:-\:57}{6}\:+\:\left(\:\dfrac{28a\:+\:5}{10}\:\right)}

\displaystyle{\implies\sf\:a\:=\:\dfrac{2a\:-\:67}{6}\:+\:\dfrac{28a\:+\:5}{10}}

\displaystyle{\implies\sf\:a\:=\:\dfrac{10\:(\:2a\:-\:67\:)\:+\:6\:(\:28a\:+\:5\:)}{6\:\times\:10}}

\displaystyle{\implies\sf\:a\:=\:\dfrac{\cancel{2}\:[\:5\:(\:2a\:-\:67\:)\:+\:3\:(\:28a\:+\:5\:)\:]}{\cancel{6}\:\times\:10}}

\displaystyle{\implies\sf\:a\:=\:\dfrac{10a\:-\:335\:+\:84a\:+\:15}{3\:\times\:10}}

\displaystyle{\implies\sf\:a\:=\:\dfrac{10a\:+\:84a\:-\:335\:+\:15}{30}}

\displaystyle{\implies\sf\:30a\:=\:94a\:-\:320}

\displaystyle{\implies\sf\:94a\:-\:30a\:=\:320}

\displaystyle{\implies\sf\:64a\:=\:320}

\displaystyle{\implies\sf\:a\:=\:\dfrac{\cancel{320}}{\cancel{64}}}

\displaystyle{\implies\sf\:a\:=\:\cancel{\dfrac{40}{8}}}

\displaystyle{\therefore\:\underline{\boxed{\red{\sf\:a\:=\:5\:}}}}

∴ The value of a is 5.

Answered by Anonymous
106

\large\underline{ \underline{ \text{Question:}}} \\

  • a -  \bigg [3a -  \frac{2a - 5}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\  \\

\large\underline{ \underline{ \text{Solution:}}} \\

Given,

  • a -  \bigg [3a -  \frac{2a - 5}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\  \\

It should done as,

\implies a -  \bigg [3a -  \frac{2a - 5}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\

\implies a -  \bigg [ \frac{3a(10) - 2a - 5}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\

\implies a -  \bigg [ \frac{30a - (2a - 5)}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\

\implies a -  \bigg [ \frac{30a - 2a  +  5}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\

\implies a -  \bigg [ \frac{28a + 5}{10}  \bigg ]  -  \bigg[  \frac{2a - 57}{6} \bigg] =  -  \frac{5}{3}  \\

\implies a -   \frac{28a  +  5}{10} -   \frac{2a - 57}{6} =  -  \frac{5}{3}  \\

\implies \frac{30(a) - 3(28a + 5) - 5(2a - 57)}{30} =  -  \frac{5}{3}  \\

\implies  \frac{30a - 84a  - 15 - 10a  + 285}{30} =  -  \frac{5}{3}  \\

\implies  \frac{- 64a  + 270}{30} =  -  \frac{5}{3}  \\

\implies  - 64a  + 270 =  -  \frac{5}{3}  \times 30 \\

\implies  - 64a  + 270 = - 5 \times 10 \\

\implies  - 64a  + 270 = - 50 \\

\implies  - 64a   = - 50 - 270 \\

\implies  - 64a   = - 320 \\

\implies  a   =  \frac{ - 320}{ - 64}  \\

\implies  a   =  \frac{  \cancel{- 64} \times 5}{ \cancel{- 64}}  \\

\implies  \boxed{ a   = 5}  \\  \\

\large\underline{ \underline{ \text{Required Answer:}}} \\

  • The value of a is 5.
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