(a +3b +2c)^2 + (a -3b +2c)^2
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Answer:
12ab+24bc
Step-by-step explanation:
using identity
a+b+c=a^2+b^2+c^2+2ab+2bc+2ca
(a+3b+2c)^2=a^2+(3b)^2+c^2+2*a*3b+2*3b*2c+2*2c*a
a^2+9b^2+c^2+6ab+12bc+4ca
(a-3b+2c)=a^2+(-3b)^2+c^2+2*a*-3b+2*-3b*2c+2*2c*a
a^2+9b^2+c^2-6ab-12bc+4ca
a^2+9b^2+c^2+6ab+12bc+4ca-(a^2+9b^2+c^2-6ab-12bc+4ca)
a^2+9b^2+c^2+6ab+12bc+4ca-a^2-9b^2-c^2+6ab+12bc-4ca
12ab+24bc Ans
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