(a-3b)^3+(3b-c)^3+(c-a)^3
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Answered by
38
if x+y+z=0
x=a-3b
y=3b-c
z=c-a
a-3b+3b-c+c-a
=0
then x+y+z =3xyz
3(a-3b)(3b-c)(c-a)
x=a-3b
y=3b-c
z=c-a
a-3b+3b-c+c-a
=0
then x+y+z =3xyz
3(a-3b)(3b-c)(c-a)
Answered by
28
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