Question

a+3b=5
3a+2b=8
solve the pairs of simultaneous equation by elimination

Answer 1

Solve [tex]a+3b=5\\ [/tex] and $3a+2b=8$ by the method of elimination

Definition:

The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods.

Step-by-step explanation:

[tex]a+3b=5\\ [/tex]             (1)

$3a+2b=8$           (2)

Multiply (1) by 3,so

$3a+9b=15$ ,subtract these and equation (2),so

[tex]3a+9b=15\\ 3a+2b=8\\ [/tex]

(-)  (-)      (-)

___________

[tex]7b=7\\ b=1[/tex]

Substitute the value of b in equation(1)

[tex]a+3b=5\\ a+3(1)=5\\ a+3=5\\ a=5-3\\ a=2[/tex]

Therefore,by solving the equations through the method of elimination,the values are [tex]a=2\\ [/tex] and $b=1$ .