Math, asked by sakhujashabad, 14 days ago

a+3b=6 , find the value of a^3+8b^3+27c^3-216​

Answers

Answered by hoihtte
0

Answer:

0

Step-by-step explanation:

Let us directly substitute a=2b+6 in the expression a

3

−8b

3

−36ab−216 as shown below:

(2b+6)

3

−8b

3

−36b(2b+6)−216

=[(2b)

3

+6

3

+(3×(2b)

2

×6)+(3×2b×6

2

)]−8b

3

−72b

2

−216b−216

(∵(x+y)

3

=x

3

+y

3

+3x

2

y+3xy

2

)

=8b

3

+216+72b

2

+216b−8b

3

−72b

2

−216b−216

=(8b

3

−8b

3

)+(72b

2

−72b

2

)+(216b−216b)+(216−216)

=0

Hence, a

3

−8b

3

−36ab−216=0 when a=2b+6.

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