Question

A + 3B forming 2C+D
This reaction is first order with
respect to reactant A and second
order with respect to reactant B.
the
conc. of
A is doubled and
( the concentration of B is halved.
the rate of reaction would​

Answer 1

Answer:

Rate=k[A][B]2

Take it one step at a time. If you double [A] you will double Rate if all else is constant.

If you halve [B] you will quarter the rate (1/2)2=1/4.

So multiply the two ratios if you are doing both changes together. 2×1/4=1/2.