Question

A-3b maths 7th class ch.10 ex.4 10 solution​

Answer 1

Answer:

If

2(x+2y

1

+

3(3x−2y)

5

=−

2

3

,

4(x+2y)

5

−

5(3x−2y)

3

=

60

61

where x+2y



=0and3x−2y



=0 Then what will be the values of x and y?

Medium

Solution

verified

Verified by Toppr

Let

x+2y

1

=U,

3x−2y

1

(I) is multiplied by 25

75U + 250V = -225

75U - 36V = 61

- + -

Subtracting 286V = - 286 V=−1,U=

3

1

∴

x+2y

1

=

3

1

,

3x−2y

1

=−1 x + 2y = 3, -3x + 2y = 1

x + 2y = 3

-3x + 2y = 1

+ - - Subtracting 4x = 2 So x=

2

1

,y=

4

5