Question

A 3cm cube of iron has one face at 100°C and
the other in a block of ice at 0°C. If k of
iron 0.2 CGS units and L for ice is 80cal/gm.
then the amount of ice that melts in 10 minutes
is (assume steady state heat transfer)​

Answer 1

Answer:

5 cube

Explanation:

0.7cgs unit l for ice is 80cal lgm then 10 min will be 5.0

Answer 2

150 grams of ice melts.

Explanation:

The temperature difference between the terminals of iron cube is ΔT= 100°c.

conductance of the iron cube is given to be K=0.2 in CGS units.

also the latent heat for ice is given as L=80 cal/gm.

From analogous current equations, the rate of flow of heat is given by the equation,

$\frac{Q}{t}= VK$

therefore, $V=$ΔT

$\frac{Q}{t} =$ΔT$K$-------------------------------------------(1)

substituting the above values in above equation 1

we, get $\frac{Q}{t}$=100×0.2=20 cal/s

$Q$=20×$t$=20×10×60=12000 cal

$Q=mL$

$m=\frac{Q}{L}$

$m=\frac{12000}{80}$ =150grams

therefore, 150 grams of ice melts in 10 minutes