A 3cm tall object is placed perpendicular to the principal axis of convex lens of focal length 15 cm. The distance of the object from the lens is 30 Find the nature position and size of the image
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So, the height of the image is 4.5 cm.
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Given :
Physics
Object Height (Ho) = 3 cm
Object Position (u) = - 20 cm
Focal length (f) = 30 cm
Convex Lens
To Find :
Image Position, size and nature
Solution :
Use lens formula
⇒1/f = 1/v - 1/u
⇒1/v = 1/f + 1/u
→ 1/v = 1/(30) + 1/(-20)
→ 1/v = 1/30 - 1/20
→1/v = (2-3)/60
1/v = -1/60
⇒ v = - 60 cm
= m = v/u = H'/Ho
→-60/-20 = H'/3
→ 3 = H'/3
→H' = 3 * 3
→ H' = 9 cm
So, the height of the image is 4.5 cm.
Explanation:
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