Physics, asked by stajbanu3283, 11 months ago

A=3i-j-4k B=-2i+4j-3k C=i+2j-k find 2A -B +3C

Answers

Answered by kiran12355

8

Explanation:

2A-B-3C =2 (3i-j-4k)-(-2i+4j-3k)+3 (i+2j-k) =6i-2j-8k+2i-4j+3k+3i+6j-3k =6i+2i+3i-2j-4j+6j-8k+3k-3k =(6+2+3)i-(2+4-6)j-(8-3+3)k =9i-0j-8k

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