A= 3i+j+ k and B= i +2j+ k
the Angle of AB is
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Step-by-step explanation:
Correct option is
А π/4
с 3л/4
The diagonals are given by AB — BC = 4i — -
2j + 4k, AB + BC = 2i − 2j These vectors have magnitudes 6 and 2√2 respectively, and their dot product is 12. Therefore the angle between them is COS -1 12 (6) (2√2) = cos -1 1 √2 or minus this value i.e.3/4 4
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