Question

A 3kg block is attached to a spring performing s.h.m and displacement is given by x= 2 cos ( 50 t ) m. Find the spring of constant of the spring.

Answer 1

Answer:

7500.

Explanation:

Refer to the material.

Answer 2

The spring constant of the spring is 7500.

Given,

The mass of the block is 3 kg.

The block is performing SHM and displacement is given by x= 2 cos ( 50 t ) m

To Find,

The spring constant of the spring.

Solution,

The general equation of a particle performing SHM is

x = Acos(ωt)

Now,

The given equation is

x= 2 cos ( 50 t )

So,

A = 2

ω = √(k/m)

50 = √(k/3)

2500 = k/3

k = 7500

Hence, the spring constant of the spring is 7500.

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