a 3kg stone is dropped from a height of 4m. what is its momentum as it strikes the ground?
Answers
Answer:
Knowing that:
v
2
f
=
v
2
i
+
2
a
s
Since the object is dropped the initial velocity is
0
m
s
:
So:
v
f
=
±
√
2
a
s
Since the velocity is in the downward direction:
v
f
=
−
√
2
a
s
Where
s
is the height or displacement
And
a
is the gravitational acceleration
v
f
=
−
√
2
(
−
9.81
m
s
2
)
(
−
4
m
)
=
−
8.86
m
s
Momentum in this case would be
m
v
f
=
(
3
k
g
)
(
−
8.86
m
s
)
=
−
26.6
k
g
m
s
Reporting this answer in one significant figure:
−
30
k
g
m
s
Answer:
Knowing that:
v
2
f
=
v
2
i
+
2
a
s
Since the object is dropped the initial velocity is
0
m
s
:
So:
v
f
=
±
√
2
a
s
Since the velocity is in the downward direction:
v
f
=
−
√
2
a
s
Where
s
is the height or displacement
And
a
is the gravitational acceleration
v
f
=
−
√
2
(
−
9.81
m
s
2
)
(
−
4
m
)
=
−
8.86
m
s
Momentum in this case would be
m
v
f
=
(
3
k
g
)
(
−
8.86
m
s
)
=
−
26.6
k
g
m
s
Reporting this answer in one significant figure:
−
30
k
g
m
s
Explanation:
hope it's helpful dr