Question

A 3m wide path run out side and around park of Length 125m and breadth 65 m. find the area of path​

Answer 1

Answer:

Here, Area of the path=Area of larger rectangle−Area of smaller rectangle.

Smaller Rectangle:

Length of smaller rectangle=125m

Breadth of smaller rectangle=65m

Larger Rectangle:

3m wide path runs all around outside smaller rectangle.

∴ Length of larger rectangle=Length of smaller rectangle+2×3

=125+6=131m

Breadth of larger rectangle=Breadth of smaller rectangle+2×3

=65+6=71m

Smaller rectangle:

Length =l=125m, Breadth=b=65m

Area of smaller rectangle=l×b=125×65=8125m2

Larger rectangle:

Length =l=131m, Breadth=b=71m

Area of larger rectangle=l×b=131×71=9301m2

Area of the path=Area of larger rectangle−Area of smaller rectangle.

=9301−8125=1176m2

∴ Area of path is 1176m2

Step-by-step explanation:

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Answer 2

Here,

Area of path = Area of larger rectangle-Area of smaller rectangle

Finding length and breadth of both rectangle

♧SMALLER RECTANGLE

Length of smaller rectangle = 125m

Breadth of smaller rectangle = 65m

♧LARGER RECTANGLE

Given, that 3m wide path runs all around outside smaller rectangle

♧Length of larger rectangle

= (Length of smaller rectangle + 2×3)

= 125+6

= 131

♧Breadth of larger rectangle

= Breadth of smaller rectangle +2×3)

=65+6

=71 m

♧Smaller rectangle

Length = l=125 m

Breadth =b=65m

$\sf \: Area \: = l \times b \\ = 125 \times 65 \\ = 8125 {m}^{2}$

♧Larger rectangle

Length= l= 131 m

Breadth =b=71 m

$\sf \: Area \: = l \times b \\ = 131 \times 71 \\ = 9301 {m}^{2}$

Now,

Area of path = Area of larger rectangle-Area of smaller rectangle

$\sf \: = (9301 - 8125) {m}^{2}$

$\sf \: = 1176 {m}^{2}$

$\sf \:∴Area \: of \: path \: is \: 1176 {m}^{2}$

HOPE IT HELPS✌