Question

A 3m wide path runs outside and around a rectangular park of length 125m and breadth 65m . Find the area of the path​

Answer 1

Answer:

Area of path is 1176m^2 

Step-by-step explanation:

Here, Area of the path=Area of larger rectangle−Area of smaller rectangle.

Smaller Rectangle:

Length of smaller rectangle=125m

Breadth of smaller rectangle=65m

Larger Rectangle:

3m wide path runs all around outside smaller rectangle.

∴ Length of larger rectangle=Length of smaller rectangle=2×3

=125+6=131m

Breadth of larger rectangle=Breadth of smaller rectangle=2×3

=65+6=71m

Smaller rectangle:

Length = l =125m, Breadth=b=65m

Area of smaller rectangle=l×b=125×65=8125m^2 

Larger rectangle:

Length = l =131m, Breadth=b=71m

Area of larger rectangle=l×b=131×71=9301m^2  

 

Area of the path=Area of larger rectangle−Area of smaller rectangle.

=9301−8125=1176m^2

∴ Area of path is 1176m^2  

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Answer 2

Answer:

The area of the path is 1176 m².

Step-by-step explanation:

Width of path = 3m

Length of the park = 125 m

Breadth of the park = 65 m

Area of the path = ??

Area of the path = Area of Park (including path) - Area of the Park

★ Area of the park (including path)

New length = 125 + (2 × 3) = 125 + 6 = 131 m

New breadth = 65 + (2 × 3) = 65 + 6 = 71 m

Area = Length × Breadth

$\sf{\longrightarrow} \: 131 \times 71$

$\sf{\longrightarrow} \:9301 \: {m}^{2}$

★ Area of park

Length = 125 m

Breadth = 65 m

Area = Length × Breadth

$\sf{\longrightarrow} \:125 \times 65$

$\sf{\longrightarrow} \:8125 \: {m}^{2}$

★ Area of path

Area of Park (including path) = 9301 m²

Area of the Park = 8125 m²

$\sf{\longrightarrow} \:9301 - 8125$

$\sf{\longrightarrow} \:1176 \: {m}^{2}$

Area of path = 1176 m²

Therefore, the area of the path is 1176 m².