Question

A 3mole of an ideal gas at 27 degree Celsius expands isothermally and reversibly from a volume of 4L to 40L the work done by the gas the work saw​

Answer 1

Given :

Moles of gas = 3

Temperature = 27°C = 300K

Initial volume = 4L

Final volume = 40L

To Find :

Work done by the gas.

Solution :

❖ Expression of work done for isothermal reversible expansion of an ideal gas is given by

$\dag\:\underline{\boxed{\bf{\red{W=-2.303\:nRT\log\bigg(\dfrac{V_f}{V_i}\bigg)}}}}$

• W denotes work done
• n denotes number of moles
• R denotes gas constant
• T denotes temperature
• Vf denotes final volume
• Vi denotes initial volume

By substituting the given values;

$\sf:\implies\:W=-2.303\:(3\times8.314\times300)\log\bigg(\dfrac{40}{4}\bigg)$

$\sf:\implies\:W=-2.303\times7482.6\log(10)$

$\sf:\implies\:W=-2.303\times7482.6\times1$

$\sf:\implies\:\underline{\boxed{\bf{\gray{W=-17232.4\:J=17.2\:kJ}}}}$

Knowledge BoosteR :

• Thermodynamics deals with study of different forms of energy and the quantitative relationship between them.
• Thermodynamic state is a set of measurable properties of the thermodynamic system that must be specified.
• Thermodynamic processes can be isothermal, adiabatic, isobaric, isochoric, cyclic, reversible or irreversible.