Question

A=3x+4y+z, B=3x-2y-z, C=x+y+z find 2A+2B+C

Answer 1

Answer:

Step-by-step explanation:

2A= 2(3x+4y+z)

    = 6x+8y+2z

2B= 2(3x-2y-z)

     = 6x-4y-2z

2C=2(x+y+z)

    =2x+2y+2z

now,

    2A+2B+2C = 6x+8y+2z +6x-4y-2z+2x+2y+2z

                        =14x+6y+2z

this we got by taking all the polynomials of the same constant in one side and adding it

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