Question

A(4,0) B(-4,0) are the two points. if p is such a point that(PA-PB)=4 then show that the locus of p is 3x²-y²=12​

Answer 1

Answer:

Answer

Vertices(±5,0)Foci(±7,0)

a=±5 and ae=±7

And e=

5

7

We know e=

1+

a

2

b

2

On squaring both sides we get:

e

2

=1+

a

2

b

2

Or

25

49

=1+

25

b

2

Or

25

b

2

=

25

24

b

2

=24

The equation of hyperbola is

25

x

2

−

24

y

2

=1

24x

2

−25y

2

=600

Hence, Option [A] and [C] are correct.