Question

A 4.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal

length 20 cm. If the distance of the object is 30 cm from the lens, find the position, nature

and size of the image. Also find its magnification.​

Answer 1

ANSWER

Height of object ho = 4 cm Focal lenght of convex lens = 20 cm Object distance u = -15 cm Image distance v = ? Image height hi = ? Lens formula: 1/v - 1/u = 1/f 1/v = 1/f + 1/u = 1/20 + 1/(-15) = -1/60 ⇒ v = - 60 cm The image distance is 60 cm on the same side of the lens as the object. Magnification m = v/u = (-60)/(-15) = 4 = hi/ho = hi/4 ⇒ hi = 4 x 4 = 16 cm The image is enlarged and erect. So a virtual, erect, enlarged image is formed at 60 cm from the optic centre on the same side of the lens as the object is positioned.

Please make me brainliest and follow me