Question

A 4.0 kg arrow is fired at 8 m/s into a stationary 20 kg block of ice as shown below. The arrow
sticks into the block of ice. What is the velocity of the arrow/ice combination after collision?

A.4.0 m/s

B. 1.3 m/s

C. 0 m/s

D. 0.5 m/s
​

Answer 1

Answer:

B=1,3

Explanation:momentum before = momentum after⇒

∴m1v2=m2v2⇒

4x8=(20+4)v2⇒

32=24v2⇒

∴v2(velocity after collision) = 1.3m/s