Question

A 4.0-kg block sitting on a frictionless surface has two horizontal forces applied to it as shown in the diagram.

Answer 1

Explanation:

f1 = 12N

f2 = 4N

mass, m = 4 kg

$acceleration = \frac{f1 - f2}{m}$

$= \frac{12 - 4}{4} = \frac{8}{4} = 2 \: m {s}^{ - 2} \: towards \: right$

Therefore , it is the correct answer.

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