Question

a 4.0 kg mass moving with speed of 2.0 m/s collides with a spring bumper of negligible mass and having a force constant 100 N/m the maximum compression of spring bumper will be​

Answer 1

Answer:

0.4 m

w= 4×10=40

x=f÷k =40÷100=0.4

Answer 2

Answer:

0.4

Explanation:

K.E = Elastic Potential Energy

1/2mv² = 1/2 kx²

mv² = kx²

x² =mv²/k

x² = (4)(2×2)/100

x² = (4) (4)/100

x² = 4/25

x² = 0.16

x = 0.4 Ans