A 4.00 g sample of an anhydrous group 2 metal nitrate is heated strongly until there is no further change. A solid residue of mass 1.37 g is formed. Which metal is present?
Answers
Answered by
17
answer : Ca
explanation : group II metal is divalent. so, chemical formula of metal nitrate should be , where M belongs to group II.
now, metal nitrate is heated strongly and as solid residue of mass 1.37g is formed. this solid residue is not other than metal.
for better understanding, chemical reaction is ...
here, it is clear 2 mole of metal nitrate forms 2 mole of metal oxide solid.
so, 1 mole of metal nitrate forms 1 mole of metal oxide solid.
or, (M + 124) g metal nitrate forms (M + 16)g of metal oxide
or, 4g of metal nitrate forms (M + 16)/(M + 124) × 4 = 1.37g
so, (M + 16)/(M + 124) = 1.37
hence, M ≈ 40 g/mol
so, atomic mass of metal is 40g/mol so, metal is not other than calcium.
explanation : group II metal is divalent. so, chemical formula of metal nitrate should be , where M belongs to group II.
now, metal nitrate is heated strongly and as solid residue of mass 1.37g is formed. this solid residue is not other than metal.
for better understanding, chemical reaction is ...
here, it is clear 2 mole of metal nitrate forms 2 mole of metal oxide solid.
so, 1 mole of metal nitrate forms 1 mole of metal oxide solid.
or, (M + 124) g metal nitrate forms (M + 16)g of metal oxide
or, 4g of metal nitrate forms (M + 16)/(M + 124) × 4 = 1.37g
so, (M + 16)/(M + 124) = 1.37
hence, M ≈ 40 g/mol
so, atomic mass of metal is 40g/mol so, metal is not other than calcium.
Similar questions
India Languages,
7 months ago
Science,
7 months ago
Economy,
7 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago
English,
1 year ago