A 4.00-kg object has a velocity of 3.00i m/s at one instant. Eight seconds later, its velocity
has increased to (8.00i +10.0j) m/s. Assuming the object was subject to a constant total
force, find (a) the components of the force and (b) its magnitude.
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3
Answer:
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Answered by
3
Explanation:
v=u+at
u=3icap
v=8icap+10jcap
t=8
on solving
a=5/8icap + 10/8jcap
force = m×a
a)force= 5/2icap + 5jcap
b)magnitude = 5√5/2
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