Question

a^4-18a^2-16=0
plz slove this quadratic equation??​

Answer 1

Answer:

a^4-18a^2-16=0

d=260=b^2-4ac

a^2=(18+$\sqrt{388}$)/2 or a^2=(18-$\sqrt{388}$)/2 this would be rejected as a sq cannot be negative

thus a= root of (18+$\sqrt{388}$)/2

Answer 2

Answer:

a^4-18a^2-16=0

d=260=b^2-4ac

a^2=

$(18+\sqrt{388}$

2 or a^2=

$(18-\sqrt{388}$

2 this would be rejected as a sq cannot be negative

• Thus a= root of
• $(18+\sqrt{388}$