A(-4, 2), B(6, 4) and C(2, -2) are vertices of triangle ABC . Find(i) the equation of midian AD (ii) the eqation if altitude BM (iii) the equation of right bisector of AB (iv) the co ordinates of centroid of triangle ABC
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3x+5y-12-0
now by comparing it to ax+by+c=0
we get a=3 b=5 c=-12
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AD is the Median
Therefore, CD BD... ( D is the midpoint of BC)
Coordinates of the D can be found by using section formula.
Let ( x,y ) be the coordinates of the centre of the circle.
(x,y) = ( 1-3/1+1 , -8-2/ 1+1 ) = ( -1, -5 )
Coordinates of point D are (-1, -5)
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