Question

A(-4,4) k(-2,p),N(4,-2)are collinear find value of p

Answer 1

Answer:

5/2

Step-by-step explanation:

first , find equation of a n using two point slope

then passes through(-2,p)

ans =5/2

as shown in fog

Answer 2

The value of p is $\frac{5}{2}$.

Step-by-step explanation:

Consider the provided information.

Three or more points are collinear if there slope is same.

Equate the slope of both points as shown below:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

For point A(-4,4) and k(-2,p) the equation of slope is:

$m=\dfrac{p-4}{-2-(-4)}$

$m=\dfrac{p-4}{-2+4}$

$m=\dfrac{p-4}{2}$

Similarly for k(-2,p) and N(4,-2) the equation of slope is:

$m=\dfrac{-2-p}{4-(-2)}$

$m=\dfrac{-2-p}{4+2}$

$m=\dfrac{-2-p}{6}$

Now equate them.

$\dfrac{p-4}{2}=\dfrac{-2-p}{6}$

$6p-24=-4-2p$

$8p=20$

$p=\frac{5}{2}$

Hence, the value of p is $\frac{5}{2}$.

If (5,7) (3,a) (6,6) are collinear points then find the value of a

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