a^4 + 4a^2-5 forming
Answers
Step-by-step explanation:
step 1 .Equation at the end of step 1
((a4) + 22a2) - 5
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring a4+4a2-5
The first term is, a4 its coefficient is 1 .
The middle term is, +4a2 its coefficient is 4 .
The last term, "the constant", is -5
Step-1 : Multiply the coefficient of the first term by the constant 1 • -5 = -5
Step-2 : Find two factors of -5 whose sum equals the coefficient of the middle term, which is 4 .
-5 + 1 = -4
-1 + 5 = 4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 5
a4 - 1a2 + 5a2 - 5
Step-4 : Add up the first 2 terms, pulling out like factors :
a2 • (a2-1)
Add up the last 2 terms, pulling out common factors :
5 • (a2-1)
Step-5 : Add up the four terms of step 4 :
(a2+5) • (a2-1)
Answer:
a^4 + 0a^3 + 4a^2 + 0a -5
Step-by-step explanation:
I think your question is Standard form
a^4 + 0a^3 + 4a^2 + 0a -5