A 4.5 Cm Needle Is Placed 12 Cm Away From A Convex Mirror Of Focal Length 15Cm Then The Location Of Image Will Be _______.
Answers
Here,
object size , h1 = 4.5 cm
object distance, u = –12 cm
focal length, f = + 15 cm
image distance , v = ?
magnification, m = ?
As. 1/u + 1/v = 1/f
1/v = 1/f – 1/u
Now,
putting u = –12 cm and f = +15cm , we get
1/v = 1/15 - 1/-12 = 4+5/60 = 9/60
v = 60/9 = 6.7 cm
✴image is formed 6.7 CM behind the convex mirror. it must be virtual and erect.
if h2 is size of image , then m = h2/h1 = -v/u
or,
m = h2/h1 = –(6.7)/–12 = 0.558
h2 = 0.558
h1 = 0.558 * 4.5 = 2.5 cm
⚡As the needle is moved further from the mirror, image moves away from the mirror till it is at focus F of the mirror the size of the image goes on decreasing.
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Answer:
h1 is equal to 2.5cm
h2 is equal 0.558
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