Physics, asked by radhikach2519, 6 months ago

A 4.5 kg block of rubber is dragged along an asphalt road what is the force of friction take coefficient of friction 1.1

Answers

Answered by MuditKesarwani

1

Answer:

49.5 N

Explanation:

On taking the value of g =10ms^-2

μ =1.1

Force of friction ,

F = μN ; (N =4.5g)

F = 1.1 × 4.5× 10

F= 49.5 N

Hope you find it helpful.....

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