Question

A 4.5 V flash light battery gives a current of 0.5 amperes, if connected across a resistance of 7.5 ohm.What is the short circuit current ?

Answer 1

Answer:

ExplanatThe emf of cell is, E=4.5V

The current in circuit  is, I=0.5A

The resistance of ammeter in circuit is, R  

TO CLEAR FULL ANSWER - cargyaani.in

Answer 2

Answer:

The short circuit current of the given circuit will be 1.10A.

Explanation:

The relation between resistance(R₁), voltage and  current through the battery can be given by;

         $Resiatance of the battery(R$₁$)$$=Voltage across the battery(V)/current through the battery(I)$

$R$₁$=V/I$

$R$₁$=4.5/0.5=9$Ω

When the battery is connected across the resistance of 7.5Ω the equivalent resistance(R₂) will be;

$1/R2=1/9$ +$1/7.5$

$R$₂=$9$×$7.5/16.5$$=4.09$Ω

The short circuit current will be(I) = $Voltage/R$₂

I$=4.5/4.09$$=$1.10A

Hence, the short circuit current will be 1.10A.