a^4-7a^2+1. factorize it
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Answer:
(x2+1+3x)(x2+1−3x)
Step-by-step explanation:
My first instinct in factoring is completing the square. x4−7x2+1 naturally becomes (x2−1)2−5x2 or (x2+1)2−9x2. Of the two the latter is a difference of squares and is thus more useful. Thus
x4−7x2+1=(x2+1)2−9x2=(x2+1+3x)(x2+1−3x)
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