Question

A (4,8), B (5,5), C (2,4), D (1,7) are the vertices of the parallelogram. Find the length of diagonal AC.


please solve this​

Answer 1

Answer:

2√5 units

Step-by-step explanation:

We know according to distance formula,

Distance between P(x1, y1) and Q(x2, y2) = $\sqrt{(x2-x1)^2 + (y2 - y1)^2}$

Therefore length of AC with A (4,8) and C (2,4) =  $\sqrt{(2-4)^2 + (4-8)^2}$

                                                                              = $\sqrt{(-2)^2 + (-4)^2}$

                                                                              = $\sqrt{(4 + 16)}$ = √ 20

                                                                                                  = 2√5 units