A= 4^86 - 2^171. How many digits would be there if a is expressed in binary base
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Answer:
Step-by-step explanation:
first 486 can be expressed as 2172
now, A= 2172-2171
=>2171(2-1) =2171
as 21 expressed as (10)2
4 (22) as (100)2
2^n as n+1.
so, answer is 172.
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