Math, asked by mohitmy9191, 1 year ago

A= 4^86 - 2^171. How many digits would be there if a is expressed in binary base

Answers

Answered by Darshil1234
0

Answer:

Step-by-step explanation:

first 486 can be expressed as 2172

now, A= 2172-2171

=>2171(2-1) =2171

as 21 expressed as (10)2

4 (22) as (100)2

2^n as n+1.

so, answer is 172.

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