Question

a^4+a^2b+b^2 factorise​

Answer 1

$a^{4} + a^{2}b + b^{2} \\=[(a^{2} )^{2}+2 \times a^{2}\times b + b^{2} ] - a^{2} b \\=( a^{2}+b)^{2} - ( a\sqrt{b})^{2} \\= ( a^{2}+b+a\sqrt{b})(a^{2}+b-a\sqrt{b})$

Therefore.,

$\red{a^{4} + a^{2}b + b^{2}}$

$\green{= ( a^{2}+b+a\sqrt{b})(a^{2}+b-a\sqrt{b})}$

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Answer 2

Answer:

ho

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