Question

A
4. A particle is projected from an inclined plane at v. = 25 root2 m/s as shown. The plane is
very long. Then time after which particle strikes the plane is :
(1)4 sec
(2) 8 sec
(3) 2 sec
(4) 6 sec

I want full explanation ​

Answer 1

Answer:

Here, u = 50 m/sec

Angle(Ѳ) = 90o

g = 9.8 m/sec2

But practically angle is 57 degree

Then T = 2usin Ѳ/g

= 2x50x sin57/9.8

= 4.2 sec

= approx 4 sec

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