Question

(a/4-b/2+1)2 expand it with suitable identites

Answer 1

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac
(a/4+b/2+1)2=(a/4)^2+(-b/2)^+1^2+2(a/4)*(-b/2)+2(-b/2)*1+2(a/4)*1

=a^2/16+b^2/4+1-ab/4-b+a/2
$(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac (a/4+b/2+1) ^{2} =(a/4)^2+(-b/2)^+1^2+2(a/4)(-b/2)+2(-b/2)1+2(a/4)1 =a^2/16+b^2/4+1-ab/4-b+a/2$

Answer 2

Step-by-step explanation:

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