Question

A^4+b^4+a^2b^2=8 and a^2+b^2+ab=4 tben find value of ab​

Answer 1

(a^2)^2+(b^2)^2+2a^2b^2-a^2b^2=8

(a^2+b^2)^2 -a^2b^2=8

(4-ab)-a^2b^2=8. { a^2-b^2 =4-ab }

16+a^2b^2-8ab-a^2b^2=8

16-8ab=8

8ab=8

ab=1 Ans.