(a^4-b^4)/(a-b)
Could you please tell me the answer and explanation?
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Answered by
2
a^4-b^4 = (a^2 + b^2)(a^2 - b^2)
= (a^2 + b^2)(a+b)(a-b)
So (a^4 - b^4)/(a-b)=(a^2 + b^2)(a+b)
= (a^2 + b^2)(a+b)(a-b)
So (a^4 - b^4)/(a-b)=(a^2 + b^2)(a+b)
shreyac9:
Can that be simplified further?
You can multiply them that will result to a^3 + b^3 + a*b*(a+b)
Answered by
1
(a^4-b^4)/(a-b)=(a^2-b^2)(a^2+b^2)/(a-b)
=(a-b)(a+b)(a^2+b^2)/(a-b)
=(a+b)(a^2+b^2)
=a^3+ab^2+a^2b+b^3
=(a-b)(a+b)(a^2+b^2)/(a-b)
=(a+b)(a^2+b^2)
=a^3+ab^2+a^2b+b^3
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