Question

a/4=b/5=c/9, prove that (a+b+c)/9=2

Answer 1

$\frac{a}{4} = \frac{b}{5} = \frac{c}{9} = k \: let \\ so \\ a = 4k \\ b = 5k \\ c = 9k \\ \frac{(a + b + c)}{9} = \frac{4k + 5k + 9k}{9} = 2k \\ if \: k = 1 \\ then \: \\ \frac{a + b + c}{9} = 2$
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