Question

A 4 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 24 cm. The distance of the object from the lens is 16 cm. Find the position, size and nature of the image formed, using the lens formula.

Answer 1

Given :-

Height of the object, h = +4cm

Focal length (convex lens) = +24cm

Object distance, u = -16cm

Formula used :-

By lens formula: 1/v - 1/u = 1/f

=> 1/v = 1/f + 1/u

=> 1/v = 1/24 + 1/(-16)

=> 1/v = 1/24 - 1/16

=> 1/v = -1/48 (taking LCM)

So, V = -48 cm

Magnification, m = v/u

=> m = -48/-16

=> m = +3

Now, m = h’/h (where, h’ is the height of the image)

=> 3 = h’/4

=> h’ = +12 cm

Thus, the image is enlarged and erect

Answer 2

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