Question

A 4 cm tall object is placed perpendicular to the principal
a convex lens of focal length 20 cm. The distance of the object from the lens is 15 cm. find the nature,
"Position and size of the image​

Answer 1

Answer:

A 4 cm tall object is placed perpendicular to the principal

a convex lens of focal length 20 cm. The distance of the object from the lens is 15 cm. find the nature,

"Position and size of the image

Explanation:

GAMER

Answer 2

Answer:

Height of object ho = 4 cm Focal lenght of convex lens = 20 cm Object distance u = -15 cm Image distance v = ? Image height hi = ? Lens formula: 1/v - 1/u = 1/f 1/v = 1/f + 1/u = 1/20 + 1/(-15) = -1/60 ⇒ v = - 60 cm The image distance is 60 cm on the same side of the lens as the object. Magnification m = v/u = (-60)/(-15) = 4 = hi/ho = hi/4 ⇒ hi = 4 x 4 = 16 cm The image is enlarged and erect. So a virtual, erect, enlarged image is formed at 60 cm from the optic centre on the same side of the lens as the object is positioned.